A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.60 |
Every 200 m thereafter or less |
$0.50 |
Roshel paid a taxi fare of $9.60. What was the greatest distance that Roshel could have travelled in the taxi? Give your answer in km.
Amount that Roshel paid for the additional distance
= 9.60 - 4.60
= $5
Number of sets of $0.50 that Roshel paid for the edditional distance
= 5 ÷ 0.50
= 10
Total additional distance that Roshel could have travelled in the taxi
= 10 x 200
= 2000 m
1000 m = 1 km
2000 m = 2000 ÷ 1000 = 2 km
Greatest distance that Roshel could have travelled in the taxi
= 1 + 2
= 3 km
Answer(s): 3 km