A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.50 |
Every 500 m thereafter or less |
$0.80 |
Diana paid a taxi fare of $8.50. What was the greatest distance that Diana could have travelled in the taxi? Give your answer in km.
Amount that Diana paid for the additional distance
= 8.50 - 4.50
= $4
Number of sets of $0.80 that Diana paid for the edditional distance
= 4 ÷ 0.80
= 5
Total additional distance that Diana could have travelled in the taxi
= 5 x 500
= 2500 m
1000 m = 1 km
2500 m = 2500 ÷ 1000 = 2.5 km
Greatest distance that Diana could have travelled in the taxi
= 1 + 2.5
= 3.5 km
Answer(s): 3.5 km