A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.90 |
Every 500 m thereafter or less |
$0.60 |
Lynn paid a taxi fare of $5.90. What was the greatest distance that Lynn could have travelled in the taxi? Give your answer in km.
Amount that Lynn paid for the additional distance
= 5.90 - 2.90
= $3
Number of sets of $0.60 that Lynn paid for the edditional distance
= 3 ÷ 0.60
= 5
Total additional distance that Lynn could have travelled in the taxi
= 5 x 500
= 2500 m
1000 m = 1 km
2500 m = 2500 ÷ 1000 = 2.5 km
Greatest distance that Lynn could have travelled in the taxi
= 1 + 2.5
= 3.5 km
Answer(s): 3.5 km