A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.10 |
Every 500 m thereafter or less |
$0.20 |
Shiyun paid a taxi fare of $4.10. What was the greatest distance that Shiyun could have travelled in the taxi? Give your answer in km.
Amount that Shiyun paid for the additional distance
= 4.10 - 2.10
= $2
Number of sets of $0.20 that Shiyun paid for the edditional distance
= 2 ÷ 0.20
= 10
Total additional distance that Shiyun could have travelled in the taxi
= 10 x 500
= 5000 m
1000 m = 1 km
5000 m = 5000 ÷ 1000 = 5 km
Greatest distance that Shiyun could have travelled in the taxi
= 1 + 5
= 6 km
Answer(s): 6 km