A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.80 |
Every 600 m thereafter or less |
$0.60 |
Yoko paid a taxi fare of $9.80. What was the greatest distance that Yoko could have travelled in the taxi? Give your answer in km.
Amount that Yoko paid for the additional distance
= 9.80 - 3.80
= $6
Number of sets of $0.60 that Yoko paid for the edditional distance
= 6 ÷ 0.60
= 10
Total additional distance that Yoko could have travelled in the taxi
= 10 x 600
= 6000 m
1000 m = 1 km
6000 m = 6000 ÷ 1000 = 6 km
Greatest distance that Yoko could have travelled in the taxi
= 1 + 6
= 7 km
Answer(s): 7 km