A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.30 |
Every 500 m thereafter or less |
$0.40 |
Raeann paid a taxi fare of $6.30. What was the greatest distance that Raeann could have travelled in the taxi? Give your answer in km.
Amount that Raeann paid for the additional distance
= 6.30 - 2.30
= $4
Number of sets of $0.40 that Raeann paid for the edditional distance
= 4 ÷ 0.40
= 10
Total additional distance that Raeann could have travelled in the taxi
= 10 x 500
= 5000 m
1000 m = 1 km
5000 m = 5000 ÷ 1000 = 5 km
Greatest distance that Raeann could have travelled in the taxi
= 1 + 5
= 6 km
Answer(s): 6 km