A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.50 |
Every 400 m thereafter or less |
$0.20 |
Gwen paid a taxi fare of $4.50. What was the greatest distance that Gwen could have travelled in the taxi? Give your answer in km.
Amount that Gwen paid for the additional distance
= 4.50 - 2.50
= $2
Number of sets of $0.20 that Gwen paid for the edditional distance
= 2 ÷ 0.20
= 10
Total additional distance that Gwen could have travelled in the taxi
= 10 x 400
= 4000 m
1000 m = 1 km
4000 m = 4000 ÷ 1000 = 4 km
Greatest distance that Gwen could have travelled in the taxi
= 1 + 4
= 5 km
Answer(s): 5 km