A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.80 |
Every 800 m thereafter or less |
$0.50 |
Sabrina paid a taxi fare of $5.80. What was the greatest distance that Sabrina could have travelled in the taxi? Give your answer in km.
Amount that Sabrina paid for the additional distance
= 5.80 - 2.80
= $3
Number of sets of $0.50 that Sabrina paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Sabrina could have travelled in the taxi
= 6 x 800
= 4800 m
1000 m = 1 km
4800 m = 4800 ÷ 1000 = 4.8 km
Greatest distance that Sabrina could have travelled in the taxi
= 1 + 4.8
= 5.8 km
Answer(s): 5.8 km