A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.70 |
Every 600 m thereafter or less |
$0.40 |
Betty paid a taxi fare of $7.70. What was the greatest distance that Betty could have travelled in the taxi? Give your answer in km.
Amount that Betty paid for the additional distance
= 7.70 - 3.70
= $4
Number of sets of $0.40 that Betty paid for the edditional distance
= 4 ÷ 0.40
= 10
Total additional distance that Betty could have travelled in the taxi
= 10 x 600
= 6000 m
1000 m = 1 km
6000 m = 6000 ÷ 1000 = 6 km
Greatest distance that Betty could have travelled in the taxi
= 1 + 6
= 7 km
Answer(s): 7 km