A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.10 |
Every 300 m thereafter or less |
$0.90 |
Raeann paid a taxi fare of $13.10. What was the greatest distance that Raeann could have travelled in the taxi? Give your answer in km.
Amount that Raeann paid for the additional distance
= 13.10 - 4.10
= $9
Number of sets of $0.90 that Raeann paid for the edditional distance
= 9 ÷ 0.90
= 10
Total additional distance that Raeann could have travelled in the taxi
= 10 x 300
= 3000 m
1000 m = 1 km
3000 m = 3000 ÷ 1000 = 3 km
Greatest distance that Raeann could have travelled in the taxi
= 1 + 3
= 4 km
Answer(s): 4 km