A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.20 |
Every 300 m thereafter or less |
$0.50 |
Xylia paid a taxi fare of $6.20. What was the greatest distance that Xylia could have travelled in the taxi? Give your answer in km.
Amount that Xylia paid for the additional distance
= 6.20 - 3.20
= $3
Number of sets of $0.50 that Xylia paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Xylia could have travelled in the taxi
= 6 x 300
= 1800 m
1000 m = 1 km
1800 m = 1800 ÷ 1000 = 1.8 km
Greatest distance that Xylia could have travelled in the taxi
= 1 + 1.8
= 2.8 km
Answer(s): 2.8 km