A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.50 |
Every 600 m thereafter or less |
$0.60 |
Mary paid a taxi fare of $10.50. What was the greatest distance that Mary could have travelled in the taxi? Give your answer in km.
Amount that Mary paid for the additional distance
= 10.50 - 4.50
= $6
Number of sets of $0.60 that Mary paid for the edditional distance
= 6 ÷ 0.60
= 10
Total additional distance that Mary could have travelled in the taxi
= 10 x 600
= 6000 m
1000 m = 1 km
6000 m = 6000 ÷ 1000 = 6 km
Greatest distance that Mary could have travelled in the taxi
= 1 + 6
= 7 km
Answer(s): 7 km