A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.50 |
Every 800 m thereafter or less |
$0.70 |
Usha paid a taxi fare of $9.50. What was the greatest distance that Usha could have travelled in the taxi? Give your answer in km.
Amount that Usha paid for the additional distance
= 9.50 - 2.50
= $7
Number of sets of $0.70 that Usha paid for the edditional distance
= 7 ÷ 0.70
= 10
Total additional distance that Usha could have travelled in the taxi
= 10 x 800
= 8000 m
1000 m = 1 km
8000 m = 8000 ÷ 1000 = 8 km
Greatest distance that Usha could have travelled in the taxi
= 1 + 8
= 9 km
Answer(s): 9 km