A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.40 |
Every 600 m thereafter or less |
$0.50 |
Fanny paid a taxi fare of $7.40. What was the greatest distance that Fanny could have travelled in the taxi? Give your answer in km.
Amount that Fanny paid for the additional distance
= 7.40 - 4.40
= $3
Number of sets of $0.50 that Fanny paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Fanny could have travelled in the taxi
= 6 x 600
= 3600 m
1000 m = 1 km
3600 m = 3600 ÷ 1000 = 3.6 km
Greatest distance that Fanny could have travelled in the taxi
= 1 + 3.6
= 4.6 km
Answer(s): 4.6 km