A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.40 |
Every 500 m thereafter or less |
$0.80 |
Jane paid a taxi fare of $10.40. What was the greatest distance that Jane could have travelled in the taxi? Give your answer in km.
Amount that Jane paid for the additional distance
= 10.40 - 2.40
= $8
Number of sets of $0.80 that Jane paid for the edditional distance
= 8 ÷ 0.80
= 10
Total additional distance that Jane could have travelled in the taxi
= 10 x 500
= 5000 m
1000 m = 1 km
5000 m = 5000 ÷ 1000 = 5 km
Greatest distance that Jane could have travelled in the taxi
= 1 + 5
= 6 km
Answer(s): 6 km