A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$2.30 |
Every 400 m thereafter or less |
$0.50 |
Betty paid a taxi fare of $5.30. What was the greatest distance that Betty could have travelled in the taxi? Give your answer in km.
Amount that Betty paid for the additional distance
= 5.30 - 2.30
= $3
Number of sets of $0.50 that Betty paid for the edditional distance
= 3 ÷ 0.50
= 6
Total additional distance that Betty could have travelled in the taxi
= 6 x 400
= 2400 m
1000 m = 1 km
2400 m = 2400 ÷ 1000 = 2.4 km
Greatest distance that Betty could have travelled in the taxi
= 1 + 2.4
= 3.4 km
Answer(s): 3.4 km