A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.10 |
Every 500 m thereafter or less |
$0.70 |
Opal paid a taxi fare of $11.10. What was the greatest distance that Opal could have travelled in the taxi? Give your answer in km.
Amount that Opal paid for the additional distance
= 11.10 - 4.10
= $7
Number of sets of $0.70 that Opal paid for the edditional distance
= 7 ÷ 0.70
= 10
Total additional distance that Opal could have travelled in the taxi
= 10 x 500
= 5000 m
1000 m = 1 km
5000 m = 5000 ÷ 1000 = 5 km
Greatest distance that Opal could have travelled in the taxi
= 1 + 5
= 6 km
Answer(s): 6 km