A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$4.30 |
Every 400 m thereafter or less |
$0.50 |
Linda paid a taxi fare of $6.30. What was the greatest distance that Linda could have travelled in the taxi? Give your answer in km.
Amount that Linda paid for the additional distance
= 6.30 - 4.30
= $2
Number of sets of $0.50 that Linda paid for the edditional distance
= 2 ÷ 0.50
= 4
Total additional distance that Linda could have travelled in the taxi
= 4 x 400
= 1600 m
1000 m = 1 km
1600 m = 1600 ÷ 1000 = 1.6 km
Greatest distance that Linda could have travelled in the taxi
= 1 + 1.6
= 2.6 km
Answer(s): 2.6 km