A taxi service charges the following rates:
Distance travelled |
Charge |
First kilometre or less |
$3.20 |
Every 200 m thereafter or less |
$0.50 |
Tina paid a taxi fare of $7.20. What was the greatest distance that Tina could have travelled in the taxi? Give your answer in km.
Amount that Tina paid for the additional distance
= 7.20 - 3.20
= $4
Number of sets of $0.50 that Tina paid for the edditional distance
= 4 ÷ 0.50
= 8
Total additional distance that Tina could have travelled in the taxi
= 8 x 200
= 1600 m
1000 m = 1 km
1600 m = 1600 ÷ 1000 = 1.6 km
Greatest distance that Tina could have travelled in the taxi
= 1 + 1.6
= 2.6 km
Answer(s): 2.6 km