The table shows the prices of croissants at two shops. The croissants are only sold in sets of 7 croissants in Sabrina's Bakery or sets of 8 croissants in Opal's Bakery.
Shop |
Price of croissants |
Sabrina's Bakery |
7 for $12 |
Opal's Bakery |
8 for $13 |
- Linda has $33.70. She wants to buy 24 croissants from Opal's Bakery. How much more money does she need to buy the 24 croissants?
- Tim has $65. He wants to buy the greatest possible number of croissants with his money from one of the two shops. What is the greatest possible number of croissants he can buy with his money?
(a)
Number of sets of 8 croissants
= 24 ÷ 8
= 3
Cost of 24 croissants
= 3 x 13
= $39
Amount that Linda needs more to buy the 24 croissants
= 39 - 33.70
= $5.30
(b)
Number of sets of 7 croissants that Tim could buy at Sabrina's Bakery
= 65 ÷ 12
= 5 r 5
Number of croissants that Tim could buy at Sabrina's Bakery
= 5 x 7
= 35
Number of sets of 8 croissants that Tim could buy at Opal's Bakery
= 65 ÷ 13
= 5 r 0
Number of croissants that Tim could buy at Opal's Bakery
= 5 x 8
= 40
(More)Greatest possible number of croissants that Tim can buy with his money = 40
Answer(s): (a) $5.30; (b) 40