Sam had 4 coins and Dylan had 3 coins. Their coins consisted of twenty-cent coins and fifty-cent coins. When all their fifty-cent coins were exchanged for twenty-cent coins, they had a total of 13 coins. How many twenty-cent coins did they have at first?
| |
Twenty-cent coins |
Fifty-cent coins |
Total |
| Before |
13 - 5 u |
2 u |
7 |
| Change |
+ 5 u |
- 2 u |
+ 3 u |
| After |
13 |
0 |
13 |
Number of coins at first
= 4 + 3
= 7
2 fifty-cent coins can be exchanged for 5 twenty-cent coins.
Increase in the number of coins after all the fifty-cent coins were exchanged for twenty-cent coins
= 5 u - 2 u
= 3 u
3 u = 13 - 7
3 u = 6
1 u = 6 ÷ 3 = 2
Number of twenty-cent coins at first
= 13 - 5 u
= 13 - 5 x 2
= 13 - 10
= 3
Answer(s): 3
