Bryan had 4 coins and David had 16 coins. Their coins consisted of twenty-cent coins and fifty-cent coins. When all their fifty-cent coins were exchanged for twenty-cent coins, they had a total of 32 coins. How many twenty-cent coins did they have at first?
|
Twenty-cent coins |
Fifty-cent coins |
Total |
Before |
32 - 5 u |
2 u |
20 |
Change |
+ 5 u |
- 2 u |
+ 3 u |
After |
32 |
0 |
32 |
Number of coins at first
= 4 + 16
= 20
2 fifty-cent coins can be exchanged for 5 twenty-cent coins.
Increase in the number of coins after all the fifty-cent coins were exchanged for twenty-cent coins
= 5 u - 2 u
= 3 u
3 u = 32 - 20
3 u = 12
1 u = 12 ÷ 3 = 4
Number of twenty-cent coins at first
= 32 - 5 u
= 32 - 5 x 4
= 32 - 20
= 12
Answer(s): 12