Xavier had 9 coins and Daniel had 2 coins. Their coins consisted of ten-cent coins and twenty-cent coins. When all their twenty-cent coins were exchanged for ten-cent coins, they had a total of 14 coins. How many ten-cent coins did they have at first?
|
Ten-cent coins |
Twenty-cent coins |
Total |
Before |
14 - 2 u |
1 u |
11 |
Change |
+ 2 u |
- 1 u |
+ 1 u |
After |
14 |
0 |
14 |
Number of coins at first
= 9 + 2
= 11
1 twenty-cent coin can be exchanged for 2 ten-cent coins.
Increase in the number of coins after all the twenty-cent coins were exchanged for ten-cent coins
= 2 u - 1 u
= 1 u
1 u = 14 - 11 = 3
Number of ten-cent coins at first
= 14 - 2 u
= 14 - 2 x 3
= 14 - 6
= 8
Answer(s): 8