In a class, 6 girls jumped an average of 1.44 m for their standing broad jump in their fitness test. The boys in the same class jumped an average of 1.55 m in the same test. The total average of the whole class was 1.52 m. How many boys were there?
|
Girls |
Boys |
Children |
Number |
6 |
1 u |
1 u + 6 |
Value |
1.44 |
1.55 |
1.52 |
Total Value |
8.64 |
1.55 u |
1.52 u + 9.12 |
Total number of boys = 1 u
Total number of children = 1 u + 6
Total length that the girls jumped
= 6 x 1.44
= 8.64 m
Total length that the boys jumped
= 1 u x 1.55
= 1.55 u
Total length that the children jumped
= 1.52(1 u + 6)
= 1.52 u + 9.12
8.64 + 1.55 u = 1.52 u + 9.12
1.55 u - 1.52 u = 9.12 - 8.64
0.03 u = 0.48
1 u = 0.48 ÷ 0.03 = 16
Number of boys
= 1 u
= 16
Answer(s): 16