The figure is made up of three triangles, BCD, EFG and HJK not drawn to scale. The area of triangle HJK is five times the area of triangle BCD. The area of triangle BCD is
13 of triangle EFG. The area of triangle BCD is 17 cm
2. What is the total area of the shaded parts?
BCD |
EFG |
HJK |
1 |
3 |
|
1 |
|
5 |
1 u |
3 u |
5 u |
Area of Triangle BCD = 1 u
1 u = 17
Area of the unshaded part
= Area of Triangle EFG - Area of Triangle BCD
= 3 u - 1 u
= 2 u
Area of the shaded part
= 5 u - 2 u
= 3 u
= 3 x 17
= 51 cm
2
Answer(s): 51 cm
2