The figure is made up of three triangles, CDE, FGH and JKL not drawn to scale. The area of triangle JKL is five times the area of triangle CDE. The area of triangle CDE is
13 of triangle FGH. The area of triangle CDE is 28 cm
2. What is the total area of the shaded parts?
CDE |
FGH |
JKL |
1 |
3 |
|
1 |
|
5 |
1 u |
3 u |
5 u |
Area of Triangle CDE = 1 u
1 u = 28
Area of the unshaded part
= Area of Triangle FGH - Area of Triangle CDE
= 3 u - 1 u
= 2 u
Area of the shaded part
= 5 u - 2 u
= 3 u
= 3 x 28
= 84 cm
2
Answer(s): 84 cm
2