CDEF is a rectangular piece of paper. Corners E and F are folded upwards as shown. ∠EHJ = 25° and ∠FHE = 17 °
- Find ∠EJH
- Find ∠FHE
(a)
∠EJH
= 180° - 90° - 25°
= 65° (Angles sum of triangle)
(b)
∠FHE
= 180° - 17° - 17° - 25° - 25°
= 96° (Angles on a straight line)
Answer(s): (a) 65° (b) 96°