PSLEOliver pushes two rods, E and F, straight into the ground until the length of each rod that is above the ground is the same.
14 of E and
16 of F are in the ground. The length of E in the ground is 8 cm longer than the length of F in the ground. What is the total length of rods E and F?
Fraction of Rod E above ground
= 1 -
14 =
34 Fraction of Rod F above ground
= 1 -
16 =
56 Heights of Rods E and F above ground are the same.
34 E =
56 F
1520 E =
1518 F
Length of Rod E more than length of Rod F
= 20 u - 18 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Total length of Rods E and F
= 20 u + 18 u
= 38 u
= 38 x 4
= 152 cm
Answer(s): 152 cm