PSLEJohn pushes two poles, R and S, straight into the ground until the length of each pole that is above the ground is the same.
16 of R and
110 of S are in the ground. The length of R in the ground is 24 cm longer than the length of S in the ground. What is the total length of poles R and S?
Fraction of Pole R above ground
= 1 -
16 =
56 Fraction of Pole S above ground
= 1 -
110 =
910 Heights of Poles R and S above ground are the same.
56 R =
910 S
4554 R =
4550 S
Length of Pole R more than length of Pole S
= 54 u - 50 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Total length of Poles R and S
= 54 u + 50 u
= 104 u
= 104 x 6
= 624 cm
Answer(s): 624 cm