PSLEGabriel pushes two sticks, C and D, straight into the ground until the length of each stick that is above the ground is the same.
13 of C and
17 of D are in the ground. The length of C in the ground is 6 cm longer than the length of D in the ground. What is the total length of sticks C and D?
Fraction of Stick C above ground
= 1 -
13 =
23 Fraction of Stick D above ground
= 1 -
17 =
67 Heights of Sticks C and D above ground are the same.
23 C =
67 D
69 C =
67 D
Length of Stick C more than length of Stick D
= 9 u - 7 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Total length of Sticks C and D
= 9 u + 7 u
= 16 u
= 16 x 3
= 48 cm
Answer(s): 48 cm