PSLEAsher pushes two rods, C and D, straight into the ground until the length of each rod that is above the ground is the same.
18 of C and
110 of D are in the ground. The length of C in the ground is 16 cm longer than the length of D in the ground. What is the total length of rods C and D?
Fraction of Rod C above ground
= 1 -
18 =
78 Fraction of Rod D above ground
= 1 -
110 =
910 Heights of Rods C and D above ground are the same.
78 C =
910 D
6372 C =
6370 D
Length of Rod C more than length of Rod D
= 72 u - 70 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Total length of Rods C and D
= 72 u + 70 u
= 142 u
= 142 x 8
= 1136 cm
Answer(s): 1136 cm