PSLEGeorge pushes two rods, U and V, straight into the ground until the length of each rod that is above the ground is the same.
18 of U and
111 of V are in the ground. The length of U in the ground is 24 cm longer than the length of V in the ground. What is the total length of rods U and V?
Fraction of Rod U above ground
= 1 -
18 =
78 Fraction of Rod V above ground
= 1 -
111 =
1011 Heights of Rods U and V above ground are the same.
78 U =
1011 V
7080 U =
7077 V
Length of Rod U more than length of Rod V
= 80 u - 77 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
Total length of Rods U and V
= 80 u + 77 u
= 157 u
= 157 x 8
= 1256 cm
Answer(s): 1256 cm