PSLEDylan pushes two poles, F and G, straight into the ground until the length of each pole that is above the ground is the same.
13 of F and
16 of G are in the ground. The length of F in the ground is 9 cm longer than the length of G in the ground. What is the total length of poles F and G?
Fraction of Pole F above ground
= 1 -
13 =
23 Fraction of Pole G above ground
= 1 -
16 =
56 Heights of Poles F and G above ground are the same.
23 F =
56 G
1015 F =
1012 G
Length of Pole F more than length of Pole G
= 15 u - 12 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Total length of Poles F and G
= 15 u + 12 u
= 27 u
= 27 x 3
= 81 cm
Answer(s): 81 cm