PSLECole pushes two rods, T and U, straight into the ground until the length of each rod that is above the ground is the same.
13 of T and
17 of U are in the ground. The length of T in the ground is 6 cm longer than the length of U in the ground. What is the total length of rods T and U?
Fraction of Rod T above ground
= 1 -
13 =
23 Fraction of Rod U above ground
= 1 -
17 =
67 Heights of Rods T and U above ground are the same.
23 T =
67 U
69 T =
67 U
Length of Rod T more than length of Rod U
= 9 u - 7 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Total length of Rods T and U
= 9 u + 7 u
= 16 u
= 16 x 3
= 48 cm
Answer(s): 48 cm