PSLEBobby pushes two rods, S and T, straight into the ground until the length of each rod that is above the ground is the same.
18 of S and
110 of T are in the ground. The length of S in the ground is 16 cm longer than the length of T in the ground. What is the total length of rods S and T?
Fraction of Rod S above ground
= 1 -
18 =
78 Fraction of Rod T above ground
= 1 -
110 =
910 Heights of Rods S and T above ground are the same.
78 S =
910 T
6372 S =
6370 T
Length of Rod S more than length of Rod T
= 72 u - 70 u
= 2 u
2 u = 16
1 u = 16 ÷ 2 = 8
Total length of Rods S and T
= 72 u + 70 u
= 142 u
= 142 x 8
= 1136 cm
Answer(s): 1136 cm