PSLEHoward pushes two rods, N and P, straight into the ground until the length of each rod that is above the ground is the same.
16 of N and
110 of P are in the ground. The length of N in the ground is 24 cm longer than the length of P in the ground. What is the total length of rods N and P?
Fraction of Rod N above ground
= 1 -
16 =
56 Fraction of Rod P above ground
= 1 -
110 =
910 Heights of Rods N and P above ground are the same.
56 N =
910 P
4554 N =
4550 P
Length of Rod N more than length of Rod P
= 54 u - 50 u
= 4 u
4 u = 24
1 u = 24 ÷ 4 = 6
Total length of Rods N and P
= 54 u + 50 u
= 104 u
= 104 x 6
= 624 cm
Answer(s): 624 cm