PSLEFred pushes two rods, A and B, straight into the ground until the length of each rod that is above the ground is the same.
16 of A and
18 of B are in the ground. The length of A in the ground is 12 cm longer than the length of B in the ground. What is the total length of rods A and B?
Fraction of Rod A above ground
= 1 -
16 =
56 Fraction of Rod B above ground
= 1 -
18 =
78 Heights of Rods A and B above ground are the same.
56 A =
78 B
3542 A =
3540 B
Length of Rod A more than length of Rod B
= 42 u - 40 u
= 2 u
2 u = 12
1 u = 12 ÷ 2 = 6
Total length of Rods A and B
= 42 u + 40 u
= 82 u
= 82 x 6
= 492 cm
Answer(s): 492 cm