PSLEPeter pushes two rods, F and G, straight into the ground until the length of each rod that is above the ground is the same.
14 of F and
16 of G are in the ground. The length of F in the ground is 8 cm longer than the length of G in the ground. What is the total length of rods F and G?
Fraction of Rod F above ground
= 1 -
14 =
34 Fraction of Rod G above ground
= 1 -
16 =
56 Heights of Rods F and G above ground are the same.
34 F =
56 G
1520 F =
1518 G
Length of Rod F more than length of Rod G
= 20 u - 18 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Total length of Rods F and G
= 20 u + 18 u
= 38 u
= 38 x 4
= 152 cm
Answer(s): 152 cm