PSLELiam pushes two rods, P and Q, straight into the ground until the length of each rod that is above the ground is the same.
14 of P and
18 of Q are in the ground. The length of P in the ground is 16 cm longer than the length of Q in the ground. What is the total length of rods P and Q?
Fraction of Rod P above ground
= 1 -
14 =
34 Fraction of Rod Q above ground
= 1 -
18 =
78 Heights of Rods P and Q above ground are the same.
34 P =
78 Q
2128 P =
2124 Q
Length of Rod P more than length of Rod Q
= 28 u - 24 u
= 4 u
4 u = 16
1 u = 16 ÷ 4 = 4
Total length of Rods P and Q
= 28 u + 24 u
= 52 u
= 52 x 4
= 208 cm
Answer(s): 208 cm