PSLENick pushes two rods, M and N, straight into the ground until the length of each rod that is above the ground is the same.
13 of M and
17 of N are in the ground. The length of M in the ground is 6 cm longer than the length of N in the ground. What is the total length of rods M and N?
Fraction of Rod M above ground
= 1 -
13 =
23 Fraction of Rod N above ground
= 1 -
17 =
67 Heights of Rods M and N above ground are the same.
23 M =
67 N
69 M =
67 N
Length of Rod M more than length of Rod N
= 9 u - 7 u
= 2 u
2 u = 6
1 u = 6 ÷ 2 = 3
Total length of Rods M and N
= 9 u + 7 u
= 16 u
= 16 x 3
= 48 cm
Answer(s): 48 cm