PSLEVincent pushes two poles, M and N, straight into the ground until the length of each pole that is above the ground is the same.
15 of M and
18 of N are in the ground. The length of M in the ground is 15 cm longer than the length of N in the ground. What is the total length of poles M and N?
Fraction of Pole M above ground
= 1 -
15 =
45 Fraction of Pole N above ground
= 1 -
18 =
78 Heights of Poles M and N above ground are the same.
45 M =
78 N
2835 M =
2832 N
Length of Pole M more than length of Pole N
= 35 u - 32 u
= 3 u
3 u = 15
1 u = 15 ÷ 3 = 5
Total length of Poles M and N
= 35 u + 32 u
= 67 u
= 67 x 5
= 335 cm
Answer(s): 335 cm