PSLEAndy pushes two rods, S and T, straight into the ground until the length of each rod that is above the ground is the same.
15 of S and
18 of T are in the ground. The length of S in the ground is 15 cm longer than the length of T in the ground. What is the total length of rods S and T?
Fraction of Rod S above ground
= 1 -
15 =
45 Fraction of Rod T above ground
= 1 -
18 =
78 Heights of Rods S and T above ground are the same.
45 S =
78 T
2835 S =
2832 T
Length of Rod S more than length of Rod T
= 35 u - 32 u
= 3 u
3 u = 15
1 u = 15 ÷ 3 = 5
Total length of Rods S and T
= 35 u + 32 u
= 67 u
= 67 x 5
= 335 cm
Answer(s): 335 cm