PSLEPeter pushes two rods, A and B, straight into the ground until the length of each rod that is above the ground is the same.
17 of A and
111 of B are in the ground. The length of A in the ground is 14 cm longer than the length of B in the ground. What is the total length of rods A and B?
Fraction of Rod A above ground
= 1 -
17 =
67 Fraction of Rod B above ground
= 1 -
111 =
1011 Heights of Rods A and B above ground are the same.
67 A =
1011 B
3035 A =
3033 B
Length of Rod A more than length of Rod B
= 35 u - 33 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Total length of Rods A and B
= 35 u + 33 u
= 68 u
= 68 x 7
= 476 cm
Answer(s): 476 cm