PSLEWesley pushes two rods, N and P, straight into the ground until the length of each rod that is above the ground is the same.
14 of N and
16 of P are in the ground. The length of N in the ground is 8 cm longer than the length of P in the ground. What is the total length of rods N and P?
Fraction of Rod N above ground
= 1 -
14 =
34 Fraction of Rod P above ground
= 1 -
16 =
56 Heights of Rods N and P above ground are the same.
34 N =
56 P
1520 N =
1518 P
Length of Rod N more than length of Rod P
= 20 u - 18 u
= 2 u
2 u = 8
1 u = 8 ÷ 2 = 4
Total length of Rods N and P
= 20 u + 18 u
= 38 u
= 38 x 4
= 152 cm
Answer(s): 152 cm