PSLESeth pushes two rods, B and C, straight into the ground until the length of each rod that is above the ground is the same.
17 of B and
111 of C are in the ground. The length of B in the ground is 14 cm longer than the length of C in the ground. What is the total length of rods B and C?
Fraction of Rod B above ground
= 1 -
17 =
67 Fraction of Rod C above ground
= 1 -
111 =
1011 Heights of Rods B and C above ground are the same.
67 B =
1011 C
3035 B =
3033 C
Length of Rod B more than length of Rod C
= 35 u - 33 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Total length of Rods B and C
= 35 u + 33 u
= 68 u
= 68 x 7
= 476 cm
Answer(s): 476 cm