PSLEAhmad pushes two rods, G and H, straight into the ground until the length of each rod that is above the ground is the same.
18 of G and
111 of H are in the ground. The length of G in the ground is 24 cm longer than the length of H in the ground. What is the total length of rods G and H?
Fraction of Rod G above ground
= 1 -
18 =
78 Fraction of Rod H above ground
= 1 -
111 =
1011 Heights of Rods G and H above ground are the same.
78 G =
1011 H
7080 G =
7077 H
Length of Rod G more than length of Rod H
= 80 u - 77 u
= 3 u
3 u = 24
1 u = 24 ÷ 3 = 8
Total length of Rods G and H
= 80 u + 77 u
= 157 u
= 157 x 8
= 1256 cm
Answer(s): 1256 cm