PSLEJeremy pushes two poles, C and D, straight into the ground until the length of each pole that is above the ground is the same.
13 of C and
16 of D are in the ground. The length of C in the ground is 9 cm longer than the length of D in the ground. What is the total length of poles C and D?
Fraction of Pole C above ground
= 1 -
13 =
23 Fraction of Pole D above ground
= 1 -
16 =
56 Heights of Poles C and D above ground are the same.
23 C =
56 D
1015 C =
1012 D
Length of Pole C more than length of Pole D
= 15 u - 12 u
= 3 u
3 u = 9
1 u = 9 ÷ 3 = 3
Total length of Poles C and D
= 15 u + 12 u
= 27 u
= 27 x 3
= 81 cm
Answer(s): 81 cm