PSLEWarren pushes two rods, Z and A, straight into the ground until the length of each rod that is above the ground is the same.
14 of Z and
18 of A are in the ground. The length of Z in the ground is 16 cm longer than the length of A in the ground. What is the total length of rods Z and A?
Fraction of Rod Z above ground
= 1 -
14 =
34 Fraction of Rod A above ground
= 1 -
18 =
78 Heights of Rods Z and A above ground are the same.
34 Z =
78 A
2128 Z =
2124 A
Length of Rod Z more than length of Rod A
= 28 u - 24 u
= 4 u
4 u = 16
1 u = 16 ÷ 4 = 4
Total length of Rods Z and A
= 28 u + 24 u
= 52 u
= 52 x 4
= 208 cm
Answer(s): 208 cm