PSLELee pushes two rods, E and F, straight into the ground until the length of each rod that is above the ground is the same.
17 of E and
111 of F are in the ground. The length of E in the ground is 14 cm longer than the length of F in the ground. What is the total length of rods E and F?
Fraction of Rod E above ground
= 1 -
17 =
67 Fraction of Rod F above ground
= 1 -
111 =
1011 Heights of Rods E and F above ground are the same.
67 E =
1011 F
3035 E =
3033 F
Length of Rod E more than length of Rod F
= 35 u - 33 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Total length of Rods E and F
= 35 u + 33 u
= 68 u
= 68 x 7
= 476 cm
Answer(s): 476 cm