PSLEDylan pushes two poles, P and Q, straight into the ground until the length of each pole that is above the ground is the same.
17 of P and
111 of Q are in the ground. The length of P in the ground is 14 cm longer than the length of Q in the ground. What is the total length of poles P and Q?
Fraction of Pole P above ground
= 1 -
17 =
67 Fraction of Pole Q above ground
= 1 -
111 =
1011 Heights of Poles P and Q above ground are the same.
67 P =
1011 Q
3035 P =
3033 Q
Length of Pole P more than length of Pole Q
= 35 u - 33 u
= 2 u
2 u = 14
1 u = 14 ÷ 2 = 7
Total length of Poles P and Q
= 35 u + 33 u
= 68 u
= 68 x 7
= 476 cm
Answer(s): 476 cm